How to subtract a number of days from todays date using PHP date function

$var = ‘2007-08-15’; $var_subtracted_date = date(‘Y-m-d’, strtotime(’-2 days’, strtotime($var)));

Explanation of PHP functions:

1)

FUNCTION date

DESCRIPTION string date ( string $format [, int $timestamp ] )

PARAMETERS USED IN THIS EXAMPLE

Y = A full numeric representation of a year, 4 digits (Examples: 1999 or 2003) m = Numeric representation of a month, with leading zeros (01 through 12) d = Day of the month, 2 digits with leading zeros (01 to 31)

2)

FUNCTION strtotime

DESCRIPTION int strtotime ( string $time [, int $now ] )

PARAMETERS

time The string to parse. Before PHP 5.0.0, microseconds weren’t allowed in the time, since PHP 5.0.0 they are allowed but ignored. now The timestamp which is used as a base for the calculation of relative dates.

EXAMPLE

echo strtotime(“now”), “\n”; echo strtotime(“10 September 2000”), “\n”; echo strtotime("+1 day"), “\n”; echo strtotime("+1 week"), “\n”; echo strtotime("+1 week 2 days 4 hours 2 seconds"), “\n”; echo strtotime(“next Thursday”), “\n”; echo strtotime(“last Monday”), “\n”;